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Question Number 152323 by mathdanisur last updated on 27/Aug/21

$${\mathrm{x}}^2\cdot \mathrm{y}=\frac{1}{18}\mathrm{and}\mathrm{x}\cdot {\mathrm{y}}^2=\frac{1}{12}$$$$\mathrm{find}{\left(\mathrm{xy}\right)}^{-2}=?$$

Answered by Olaf_Thorendsen last updated on 27/Aug/21

$$x^{2}y=\frac{1}{18}\mathrm{and}{xy}^2=\frac{1}{12}$$$$\Rightarrow \left(x^{2}y\right)\left({xy}^2\right)={\left(xy\right)}^3=\frac{1}{12\times 18}=\frac{1}{216}$$$$xy=\frac{1}{\sqrt[3]{216}}=\frac{1}{6}$$$${\left(xy\right)}^{-2}=6^2=36$$

Commented by mathdanisur last updated on 27/Aug/21

$$\mathrm{Thank}\mathrm{You}\mathrm{Ser}$$

Commented by otchereabdullai@gmail.com last updated on 27/Aug/21

$$\mathrm{nice}\mathrm{one}!$$

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