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Question Number 152365 by mathdanisur last updated on 27/Aug/21

Answered by ghimisi last updated on 28/Aug/21

a=x+y;b=y+z;c=x+z  p=x+y+z;q=ab+bc+ac;r=abc  ⇔....⇔p^3 +9r≥4pq⇔schur

a=x+y;b=y+z;c=x+zp=x+y+z;q=ab+bc+ac;r=abc....p3+9r4pqschur

Commented by mathdanisur last updated on 28/Aug/21

Thank you Ser nice

ThankyouSernice

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