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Question Number 152450 by fotosy2k last updated on 28/Aug/21

Commented by fotosy2k last updated on 28/Aug/21

$$plshelp$$

Answered by JDamian last updated on 28/Aug/21

$$a_n=\frac{1}{3^n}+1+\frac{1}{n}\mathrm{\forall }n\in \mathbb{N}$$$$a_n>1\Rightarrow \left(B\right)and\left(D\right)arediscarded$$$$$$$$a_{n}isdecreasing\mathrm{\forall }n\Rightarrow a_{1}isthehighest$$$$a_1=\frac{1}{3^1}+1+\frac{1}{1}=\frac{1}{3}+2=\frac{7}{3}$$

Commented by fotosy2k last updated on 30/Aug/21

$$thankyou$$

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