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Question Number 152472 by talminator2856791 last updated on 28/Aug/21

$$$$$$\mathrm{\Gamma }\left(\frac{3}{4}\right)=\exp (-\frac{3\gamma }{4}+{\int }_0^{1}f\left(x\right)dx)$$$$$$$$\mathrm{find}f\left(x\right)$$$$$$

Answered by mindispower last updated on 28/Aug/21

$$f\left(x\right)=\frac{3\gamma }{4}+ln\left(\mathrm{\Gamma }\left(\frac{3}{4}\right)\right)$$

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