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Question Number 152571 by Gbenga last updated on 29/Aug/21

 2log4^x +9logx^4 =9  find x

2log4x+9logx4=9findx

Answered by mr W last updated on 29/Aug/21

log (4^(2x) ×x^(36) )=9  4^(2x) ×x^(36) =10^9   2^(x/9) ×x=±10^(1/4)   e^((x/9)ln 2) ×x=±10^(1/4)   e^((x/9)ln 2) ×((xln 2)/9)=±10^(1/4) ×((ln 2)/9)  ((xln 2)/9)=W(±10^(1/4) ×((ln 2)/9))  ⇒x=(9/(ln 2))W(±10^(1/4) ×((ln 2)/9))       = { (((9/(ln 2))W(−10^(1/4) ×((ln 2)/9))= { (((9/(ln 2))×(−3.128713)=−40.624008)),(((9/(ln 2))×(−0.160858)=2.088621)) :})),(((9/(ln 2))W(10^(1/4) ×((ln 2)/9))=(9/(ln 2))×0.121311=1.575133)) :}

log(42x×x36)=942x×x36=1092x9×x=±1014ex9ln2×x=±1014ex9ln2×xln29=±1014×ln29xln29=W(±1014×ln29)x=9ln2W(±1014×ln29)={9ln2W(1014×ln29)={9ln2×(3.128713)=40.6240089ln2×(0.160858)=2.0886219ln2W(1014×ln29)=9ln2×0.121311=1.575133

Commented by Tawa11 last updated on 29/Aug/21

Great sir

Greatsir

Commented by Gbenga last updated on 31/Aug/21

great sir

greatsir

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