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Question Number 152617 by eman_64 last updated on 30/Aug/21

Commented by mr W last updated on 30/Aug/21

$$L=\underset{x\to \frac{\pi }{6}}{\lim }\frac{-\cos (\frac{\pi }{6}-x)}{-4\cos x}=\frac{1}{4\times \frac{\sqrt{3}}{2}}=\frac{1}{2\sqrt{3}}$$

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