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Question Number 152715 by Tawa11 last updated on 31/Aug/21

$$\mathrm{By}\mathrm{eliminating}\theta ,\mathrm{show}\mathrm{that}{\mathrm{x}}^2=-{\mathrm{y}}^2,$$$$\mathrm{if}\mathrm{x}{\sin }^3\theta +\mathrm{y}{\cos }^3\theta =\sin \theta \mathrm{and}\mathrm{x}\sin \theta -\mathrm{y}\cos \theta =0$$

Commented by Tawa11 last updated on 02/Sep/21

$$\mathrm{Thanks}\mathrm{sir}.\mathrm{God}\mathrm{bless}\mathrm{you}$$

Commented by mr W last updated on 01/Sep/21

$$questionisclearlywrong.$$$$x^2=-y^{2}meanssimplyx=y=0.$$

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