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Question Number 152723 by Tawa11 last updated on 31/Aug/21

Answered by Olaf_Thorendsen last updated on 31/Aug/21

$${\mathrm{V}}_{5\mathrm{\Omega }}=5\mathrm{\Omega }\times {\mathrm{I}}_{5\mathrm{\Omega }}=5\mathrm{\Omega }\times 2\mathrm{A}=10\mathrm{V}$$$${\mathrm{V}}_{10\mathrm{\Omega }}={\mathrm{V}}_{5\mathrm{\Omega }}=10\mathrm{V}$$$${\mathrm{I}}_{10\mathrm{\Omega }}=\frac{{\mathrm{V}}_{10\mathrm{\Omega }}}{10\mathrm{\Omega }}=\frac{10\mathrm{V}}{10\mathrm{\Omega }}=1\mathrm{A}$$$${\mathrm{I}}_{20\mathrm{\Omega }}={\mathrm{I}}_{5\mathrm{\Omega }}+{\mathrm{I}}_{10\mathrm{\Omega }}=2\mathrm{A}+1\mathrm{A}=3\mathrm{A}$$$${\mathrm{V}}_{20\mathrm{\Omega }}=20\mathrm{\Omega }\times {\mathrm{I}}_{20\mathrm{\Omega }}=20\mathrm{\Omega }\times 3\mathrm{A}=60\mathrm{V}$$

Commented by Tawa11 last updated on 31/Aug/21

$$\mathrm{Wow},\mathrm{thanks}\mathrm{sir}.\mathrm{I}\mathrm{appreciate}.\mathrm{God}\mathrm{bless}\mathrm{you}.$$

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