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Question Number 152791 by mathdanisur last updated on 01/Sep/21

Answered by MJS_new last updated on 02/Sep/21

(xy−1)^2 −16(x−1)(y−1)≥0 x^2 y^2 −18xy+16x+16y−15≥0 x=3+p∧y=3+q∧p≥0∧q≥0 p^2 q^2 +6pq(p+q+3)+9(p^2 +q^2 )+16(p+q)≥0 which obviously is true

(xy−1)2−16(x−1)(y−1)⩾0x2y2−18xy+16x+16y−15⩾0x=3+p∧y=3+q∧p⩾0∧q⩾0p2q2+6pq(p+q+3)+9(p2+q2)+16(p+q)⩾0whichobviouslyistrue

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