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Question Number 153050 by DELETED last updated on 04/Sep/21

Answered by DELETED last updated on 04/Sep/21

$$\mathrm{M}\stackrel{+4}{\mathrm{n}}{\stackrel{-2}{\mathrm{O}}}_2\to \mathrm{\Sigma }\mathrm{biloks}=0$$$$\mathrm{Mn}+(-2\times 2)=0\to \mathrm{Mn}-4=0$$$$\mathrm{Mn}=+4$$$$\mathrm{M}\stackrel{+4}{\mathrm{n}}\to \mathrm{M}\stackrel{+2}{\mathrm{n}}\mathrm{disebut}\mathrm{reduksi}$$$$\mathrm{C}\stackrel{-1}{\mathrm{l}}\to \mathrm{C}{\stackrel{0}{\mathrm{l}}}_2\mathrm{disebut}\mathrm{oksidasi}$$$$\mathrm{kalau}\mathrm{digabung}\mathrm{disebut}\mathrm{Redoks}$$$$\mathrm{sudah}\mathrm{setara},\mathrm{jumlah}\mathrm{atom}\mathrm{masing}$$$$\mathrm{masing}\mathrm{unsur}\mathrm{sama}\mathrm{sblm}\mathrm{dan}$$$$\mathrm{sesudah}\mathrm{reaksi}.$$

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