Math Question and Answers


Question and Answers Forum

All Questions Topic List
None Questions
Previous in All Question Next in All Question
Previous in None Next in None
Question Number 153054 by daus last updated on 04/Sep/21

	Answered by bobhans last updated on 04/Sep/21
	${ ((g(x)=1−2x)),((f(x)=kx^2 +m)) :} ⇒(f•g)(x)=x^2 −2x+5 ⇒k(1−2x)^2 +m = x^2 −2x+5 ⇒k(4x^2 −4x+1)+m=x^2 −2x+5 ⇒4kx^2 −4kx+k+m=x^2 −2x+5 → { ((4k=1 ⇒k=(1/4) but)),((4k=2⇒k=(1/2))) :} something wrong the question$
	${\begin{cases} g (x) = 1 - 2 x \\ f (x) = {k x}^{2} + m \end{cases} \Rightarrow (f ∙ g) (x) = x^{2} - 2 x + 5$ $\Rightarrow k {(1 - 2 x)}^{2} + m = x^{2} - 2 x + 5$ $\Rightarrow k (4 x^{2} - 4 x + 1) + m = x^{2} - 2 x + 5$ $\Rightarrow 4 {k x}^{2} - 4 k x + k + m = x^{2} - 2 x + 5$ $\to {\begin{cases} 4 k = 1 \Rightarrow k = \frac{1}{4} b u t \\ 4 k = 2 \Rightarrow k = \frac{1}{2} \end{cases}$ $s o m e t h i n g w r o n g t h e q u e s t i o n$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum