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Question Number 153256 by Lekhraj last updated on 06/Sep/21

Commented by MJS_new last updated on 06/Sep/21

x<y  x=((25)/(9t))∧y=((25t)/9)  t=(√(5/3)) ⇒ (x/y)=(3/5)  (for y<x we get (x/y)=(5/3))

$${x}<{y} \\ $$$${x}=\frac{\mathrm{25}}{\mathrm{9}{t}}\wedge{y}=\frac{\mathrm{25}{t}}{\mathrm{9}} \\ $$$${t}=\sqrt{\frac{\mathrm{5}}{\mathrm{3}}}\:\Rightarrow\:\frac{{x}}{{y}}=\frac{\mathrm{3}}{\mathrm{5}} \\ $$$$\left(\mathrm{for}\:{y}<{x}\:\mathrm{we}\:\mathrm{get}\:\frac{{x}}{{y}}=\frac{\mathrm{5}}{\mathrm{3}}\right) \\ $$

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