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Question Number 153593 by tabata last updated on 08/Sep/21

$$\mathit{S}\mathit{o}\mathit{l}\mathit{v}\mathit{e}:\left(\mathit{s}\mathit{i}\mathit{n}\left(2\mathit{x}\right)\right)!=2$$

Answered by puissant last updated on 08/Sep/21

$$\left(sin\left(2x\right)\right)!=2!\Rightarrow sin\left(2x\right)=2$$$$\Rightarrow \frac{e^{2ix}-e^{-2ix}}{2i}=2$$$$\Rightarrow e^{4ix}-1=4{ie}^{2ix}$$$$\Rightarrow e^{i4x}-4{ie}^{2ix}-1=0$$$$z=e^{i2x},wehave{z}^2-4iz-1=0..$$$$...........$$

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