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Question Number 153714 by pete last updated on 09/Sep/21

$$\mathrm{How}\mathrm{many}\mathrm{three}-\mathrm{digit}\mathrm{numbers}\mathrm{can}\mathrm{be}$$$$\mathrm{formed}\mathrm{using}\mathrm{the}\mathrm{digits}2,3,5,7,8\mathrm{if}$$$$\mathrm{the}\mathrm{number}\mathrm{is}\mathrm{odd}\mathrm{and}\mathrm{no}\mathrm{digit}\mathrm{is}\mathrm{repeted}?$$

Answered by EDWIN88 last updated on 09/Sep/21

$$=P_1^3\times P_2^4=\frac{3!}{2!}\times \frac{4!}{2!}=6\times 6=36$$

Answered by puissant last updated on 09/Sep/21

$$A_3^1\times A_4^2=\frac{3!}{(3-1)!}\times \frac{4!}{(4-2)!}$$$$=3\times 4\times 3$$$$=36..$$

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