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Question Number 154065 by peter frank last updated on 13/Sep/21

	Answered by Rasheed.Sindhi last updated on 14/Sep/21

	$A r e a o f t h e b a d g e = T w o s e m i - c i r c l e s$ $+ O n e r e c t a n g l e$ $2 (\frac{π x^{2}}{2}) + x y = 20$ $π x^{2} + x y = 20$ $y = \frac{20 - π x^{2}}{x}$ $P e r i m e t e r = T w o s e m i - c i r c l e s$ $+ 2 l e n g t h s + 2 w i d t h s$ $p = 2 π x + 2 y + 2 x$ $= 2 π x + 2 (\frac{20 - π x^{2}}{x}) + 2 x$ $= \frac{2 π x^{2} + 40 - 2 π x^{2} + 2 x^{2}}{x}$ $= 2 x + \frac{40}{x}$
	Commented by peter frank last updated on 14/Sep/21

	$thank you$
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