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Question Number 154330 by DELETED last updated on 17/Sep/21

Answered by DELETED last updated on 17/Sep/21

$$\mathrm{Jawab}:$$$$\mathrm{Dik}={\mathrm{K}}_1=8,318\times {10}^{-7}$$$${\mathrm{K}}_2=5,248\times {10}^{-10}$$$$\left[{\mathrm{H}}^{+}\right]={10}^{-8}$$$$\mathrm{\Sigma }{\mathrm{CO}}_2=2,3\mathrm{mMol}$$$$\left[{\mathrm{CO}}_3^{-2}\right]=\frac{\mathrm{DIC}}{[1+\frac{\left[{\mathrm{H}}^{+}\right]}{{\mathrm{k}}_2}+\frac{{\left[{\mathrm{H}}^{+}\right]}^2}{{\mathrm{k}}_1.{\mathrm{k}}_2}]}$$$$=\frac{2,3}{1+\frac{{10}^{-8}}{{10}^{-9,28}}+\frac{{\left[{10}^{-8}\right]}^2}{{10}^{-6,8}\times {10}^{-9,28}}}$$$$=\frac{2,3}{1+{10}^{1,28}+{10}^{0,8}}$$$$=\frac{2,3}{1+19,054+6,309}$$$$=\frac{2,3}{26,36}=0,0873//$$

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