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Question Number 154514 by 0731619 last updated on 19/Sep/21

Commented by mr W last updated on 19/Sep/21

$$thereisnotmuchtosolve!{it}^{\prime }sa$$$$matterofdefinition.$$$$\left(\begin{array}{c}2n\\ n\end{array}\right)=\frac{\left(2n\right)!}{{(n!)}^2}$$

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