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Question Number 154777 by Khalmohmmad last updated on 21/Sep/21

Answered by john_santu last updated on 21/Sep/21

$$itshouldbe\underset{k\to 5}{\lim }\left(\frac{k^2-25}{k-5}\right)=k+5$$$$orif\underset{x\to 5}{\lim }\left(\frac{k^2-25}{k-5}\right)=\left(\frac{k^2-25}{k-5}\right)\times \underset{x\to 5}{\lim }\left(1\right)$$$$=\frac{k^2-25}{k-5}=k+5$$

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