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Question Number 154846 by SANOGO last updated on 22/Sep/21

$$y^{\prime }=\frac{ycos\left(x\right)}{1+2y^2}$$$$trouvelasolutiondelequationdifferentielle$$

Commented by tabata last updated on 22/Sep/21

$$\frac{\mathit{d}\mathit{y}}{\mathit{d}\mathit{x}}=\frac{\mathit{y}}{1+2{\mathit{y}}^2}\mathit{c}\mathit{o}\mathit{s}\left(\mathit{x}\right)$$$$$$$$\frac{1+2{\mathit{y}}^2}{\mathit{y}}\mathit{d}\mathit{y}=\mathit{c}\mathit{o}\mathit{s}\left(\mathit{x}\right)\mathit{d}\mathit{x}$$$$$$$$\mathit{l}\mathit{n}\mid \mathit{y}\mid +{\mathit{y}}^2=\mathit{s}\mathit{i}\mathit{n}\left(\mathit{x}\right)+\mathit{c}$$$$$$$$\therefore {\mathit{y}}^2+\mathit{l}\mathit{n}\mid \mathit{y}\mid -\mathit{s}\mathit{i}\mathit{n}\left(\mathit{x}\right)=\mathit{c}$$$$$$$$⟨\mathit{M}.\mathit{T}⟩$$

Commented by SANOGO last updated on 22/Sep/21

$$mercibien$$

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