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Question Number 154910 by mr W last updated on 23/Sep/21

Commented by mr W last updated on 23/Sep/21

tetrahedron T−ABC has edge lengthes  a,b,c,u,v,w.  the faces of tetrahedron T′−A′B′C′  have the distances d_1 ,d_2 ,d_3 ,d_4  to the  corresponding faces of T−ABC.  find the volume of new tetrahedron.

tetrahedronTABChasedgelengthesa,b,c,u,v,w.thefacesoftetrahedronTABChavethedistancesd1,d2,d3,d4tothecorrespondingfacesofTABC.findthevolumeofnewtetrahedron.

Commented by Rasheed.Sindhi last updated on 23/Sep/21

Guess  V ′=(1+(((face1^(area) )d_1 +(face2^(area) )d_2 +(face3^(area) )d_3 +(face4^(area) )d_4 )/(3V)))^3 .V

GuessV=(1+(face1area)d1+(face2area)d2+(face3area)d3+(face4area)d43V)3.V

Answered by mr W last updated on 24/Sep/21

tetrahedron T−ABC:  edges: a,b,c,u,v,w  volume: V in terms of a,b,c,u,v,w^(∗))   face 1: ΔTBC, area A_1  in terms of a,v,w ^(∗∗))   face 2: ΔTCA, area A_2  in terms of b,w,u  face 3: ΔTAB, area A_3  in terms of c,u,v  face 4: ΔABC, area A_4  in terms of a,b,c  radius of insphere of T−ABC: r  ((r(A_1 +A_2 +A_3 +A_4 ))/3)=V  tetrahedrons T−ABC and T′−A′B′C′  are similar.  say the edges of T′−A′B′C′  are a′,b′,c′,u′,v′,w′ and  a′=ka, b′=kb, c′=kc, u′=ku, v′=kv, w′=kw  with k=factor of magnification.    we have  area of face 1 of  T′−A′B′C′ A_1 ′=k^2 A_1   area of face 2 of  T′−A′B′C′ A_2 ′=k^2 A_2   area of face 3 of  T′−A′B′C′ A_3 ′=k^2 A_3   area of face 4 of  T′−A′B′C′ A_4 ′=k^2 A_4   volume of T′−A′B′C′ V′=k^3 V    on the other side,  V′=((A_1 ′(r+d_1 ))/3)+((A_2 ′(r+d_2 ))/3)+((A_3 ′(r+d_3 ))/3)+((A_4 ′(r+d_4 ))/3)  V′=((k^2 A_1 (r+d_1 ))/3)+((k^2 A_2 (r+d_2 ))/3)+((k^2 A_3 (r+d_3 ))/3)+((k^2 A_4 (r+d_4 ))/3)  V′=((k^2 [(A_1 +A_2 +A_3 +A_4 )r+A_1 d_1 +A_2 d_2 +A_3 d_3 +A_4 d_4 ])/3)  V′=((k^2 (3V+A_1 d_1 +A_2 d_2 +A_3 d_3 +A_4 d_4 ))/3)  ((k^2 (3V+A_1 d_1 +A_2 d_2 +A_3 d_3 +A_4 d_4 ))/3)=k^3 V  ⇒k=1+((A_1 d_1 +A_2 d_2 +A_3 d_3 +A_4 d_4 )/(3V))  volume of T′−A′B′C′ is  V′=(1+((A_1 d_1 +A_2 d_2 +A_3 d_3 +A_4 d_4 )/(3V)))^3 V  ___________________________  ^(∗))  using Euler′ formula, see Q40469  ^(∗∗))  using Heron′s formula

tetrahedronTABC:edges:a,b,c,u,v,wvolume:Vintermsofa,b,c,u,v,w)face1:ΔTBC,areaA1intermsofa,v,w)face2:ΔTCA,areaA2intermsofb,w,uface3:ΔTAB,areaA3intermsofc,u,vface4:ΔABC,areaA4intermsofa,b,cradiusofinsphereofTABC:rr(A1+A2+A3+A4)3=VtetrahedronsTABCandTABCaresimilar.saytheedgesofTABCarea,b,c,u,v,wanda=ka,b=kb,c=kc,u=ku,v=kv,w=kwwithk=factorofmagnification.wehaveareaofface1ofTABCA1=k2A1areaofface2ofTABCA2=k2A2areaofface3ofTABCA3=k2A3areaofface4ofTABCA4=k2A4volumeofTABCV=k3Vontheotherside,V=A1(r+d1)3+A2(r+d2)3+A3(r+d3)3+A4(r+d4)3V=k2A1(r+d1)3+k2A2(r+d2)3+k2A3(r+d3)3+k2A4(r+d4)3V=k2[(A1+A2+A3+A4)r+A1d1+A2d2+A3d3+A4d4]3V=k2(3V+A1d1+A2d2+A3d3+A4d4)3k2(3V+A1d1+A2d2+A3d3+A4d4)3=k3Vk=1+A1d1+A2d2+A3d3+A4d43VvolumeofTABCisV=(1+A1d1+A2d2+A3d3+A4d43V)3V___________________________)usingEulerformula,seeQ40469)usingHeronsformula

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