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Question Number 154910 by mr W last updated on 23/Sep/21
Commented by mr W last updated on 23/Sep/21
tetrahedronT−ABChasedgelengthesa,b,c,u,v,w.thefacesoftetrahedronT′−A′B′C′havethedistancesd1,d2,d3,d4tothecorrespondingfacesofT−ABC.findthevolumeofnewtetrahedron.
Commented by Rasheed.Sindhi last updated on 23/Sep/21
GuessV′=(1+(face1area)d1+(face2area)d2+(face3area)d3+(face4area)d43V)3.V
Answered by mr W last updated on 24/Sep/21
tetrahedronT−ABC:edges:a,b,c,u,v,wvolume:Vintermsofa,b,c,u,v,w∗)face1:ΔTBC,areaA1intermsofa,v,w∗∗)face2:ΔTCA,areaA2intermsofb,w,uface3:ΔTAB,areaA3intermsofc,u,vface4:ΔABC,areaA4intermsofa,b,cradiusofinsphereofT−ABC:rr(A1+A2+A3+A4)3=VtetrahedronsT−ABCandT′−A′B′C′aresimilar.saytheedgesofT′−A′B′C′area′,b′,c′,u′,v′,w′anda′=ka,b′=kb,c′=kc,u′=ku,v′=kv,w′=kwwithk=factorofmagnification.wehaveareaofface1ofT′−A′B′C′A1′=k2A1areaofface2ofT′−A′B′C′A2′=k2A2areaofface3ofT′−A′B′C′A3′=k2A3areaofface4ofT′−A′B′C′A4′=k2A4volumeofT′−A′B′C′V′=k3Vontheotherside,V′=A1′(r+d1)3+A2′(r+d2)3+A3′(r+d3)3+A4′(r+d4)3V′=k2A1(r+d1)3+k2A2(r+d2)3+k2A3(r+d3)3+k2A4(r+d4)3V′=k2[(A1+A2+A3+A4)r+A1d1+A2d2+A3d3+A4d4]3V′=k2(3V+A1d1+A2d2+A3d3+A4d4)3k2(3V+A1d1+A2d2+A3d3+A4d4)3=k3V⇒k=1+A1d1+A2d2+A3d3+A4d43VvolumeofT′−A′B′C′isV′=(1+A1d1+A2d2+A3d3+A4d43V)3V___________________________∗)usingEuler′formula,seeQ40469∗∗)usingHeron′sformula
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