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Question Number 155017 by SANOGO last updated on 24/Sep/21

$${\int }_0^{\frac{3}{2}}E\left(x^2\right)dx;avecE\left(x\right)lapartieentiere$$

Answered by puissant last updated on 24/Sep/21

$$K={\int }_0^{\frac{3}{2}}E\left(x^2\right)dx$$$$={\int }_0^{1}E\left(x^2\right)dx+{\int }_1^{\sqrt{2}}E\left(x^2\right)dx+{\int }_{\sqrt{2}}^{\frac{3}{2}}E\left(x^2\right)dx$$$$=0(1-0)+1(\sqrt{2}-1)+2(\frac{3}{2}-\sqrt{2})$$$$=0+\sqrt{2}-1+3-2\sqrt{2}=2-\sqrt{2}..$$$$\therefore \because K={\int }_0^{\frac{3}{2}}E\left(x^2\right)dx=2-\sqrt{2}..$$

Commented by SANOGO last updated on 24/Sep/21

$$mercibiencourage$$

Commented by puissant last updated on 24/Sep/21

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Commented by tabata last updated on 25/Sep/21

$$sirhowyougivetheintervalinthisform$$$$canyougivemetheformullaofE\left(x\right)?$$

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