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Question Number 155122 by saly last updated on 25/Sep/21

Commented by benhamimed last updated on 25/Sep/21

/x−3/+3−x≠0 /x−3/= { ((x−3 ;x≥3)),((3−x ;x≤3)) :} /x−3/+3−x= { ((0 ;x≥3)),((6−2x ;x≤0)) :} D=]−∞;3[

/x−3/+3−x≠0/x−3/={x−3;x⩾33−x;x⩽3/x−3/+3−x={0;x⩾36−2x;x⩽0D=]−∞;3[

Commented by saly last updated on 25/Sep/21

thank you

thankyou

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