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Question Number 155174 by Fridunatjan08 last updated on 26/Sep/21

$$Findnif:$$$${133}^5+{110}^5+{84}^5+{27}^5=n^5$$

Answered by MJS_new last updated on 26/Sep/21

$$144$$

Commented by Fridunatjan08 last updated on 02/Oct/21

$$pleasesirshowmethesteps.$$

Answered by Skabetix last updated on 26/Sep/21

$${({133}^5+{110}^5+{84}^5+{27}^5)}^{\left(1/5\right)}=n=144$$

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