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Question Number 155174 by Fridunatjan08 last updated on 26/Sep/21

Find n if:  133^5 +110^5 +84^5 +27^5 =n^5

$${Find}\:{n}\:{if}: \\ $$$$\mathrm{133}^{\mathrm{5}} +\mathrm{110}^{\mathrm{5}} +\mathrm{84}^{\mathrm{5}} +\mathrm{27}^{\mathrm{5}} ={n}^{\mathrm{5}} \\ $$

Answered by MJS_new last updated on 26/Sep/21

144

$$\mathrm{144} \\ $$

Commented by Fridunatjan08 last updated on 02/Oct/21

please sir show me the steps.

$${please}\:{sir}\:{show}\:{me}\:{the}\:{steps}. \\ $$

Answered by Skabetix last updated on 26/Sep/21

(133^5 +110^5 +84^5 +27^5 )^((1/5)) =n=144

$$\left(\mathrm{133}^{\mathrm{5}} +\mathrm{110}^{\mathrm{5}} +\mathrm{84}^{\mathrm{5}} +\mathrm{27}^{\mathrm{5}} \right)^{\left(\mathrm{1}/\mathrm{5}\right)} ={n}=\mathrm{144} \\ $$

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