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Question Number 155212 by ajfour last updated on 27/Sep/21

Commented by mr W last updated on 27/Sep/21

$$\cos \theta =\frac{p}{1}\Rightarrow \cos \theta =p$$$$\frac{c}{\sin \theta }=p\sin \theta \Rightarrow {\sin }^2\theta =\frac{c}{p}$$$$\frac{c}{p}+p^2=1$$$$p^3-p+c=0$$$$...$$

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