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Question Number 155242 by aliyn last updated on 27/Sep/21

$$\mathit{t}\mathit{h}\mathit{e}\mathit{v}\mathit{a}\mathit{l}\mathit{u}\mathit{e}\mathit{o}\mathit{f}\mathit{\beta }(2,n)\mathit{i}\mathit{s}?$$

Commented by tabata last updated on 27/Sep/21

$$=\frac{\mathrm{\Gamma }2\mathrm{\Gamma }\left(n\right)}{\mathrm{\Gamma }(n+2)}=\frac{(n-1)!}{(n+1)!}=\frac{(n-1)!}{n(n+1)(n-1)!}=\frac{1}{n(n+1)}$$

Answered by puissant last updated on 27/Sep/21

$$\beta (2,n)=\frac{\mathrm{\Gamma }\left(2\right)\mathrm{\Gamma }\left(n\right)}{\mathrm{\Gamma }(n+2)}=\frac{1(n-1)!}{(n+1)!}=\frac{1}{n(n+1)}..$$$$=\frac{1}{n}-\frac{1}{n+1}..$$

Commented by aliyn last updated on 27/Sep/21

$$sir\mathrm{\Gamma }2=\mathrm{\Gamma }(1+1)=1\times 1!=1how\mathrm{\Gamma }2=2?$$

Commented by puissant last updated on 27/Sep/21

$$Thanks..$$

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