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Question Number 155252 by mnjuly1970 last updated on 27/Sep/21
∫0π2x.sin2(x).ln(sin(x))dx
Answered by phanphuoc last updated on 28/Sep/21
lnsinx=−ln2−∑k=1∞cos(2kx)k→I=∫0∞xsin2x(−ln2−Σcos(2kx)k)dx=−ln2∫0∞xsin2xdx−Σ12kx(1−cos2x)cos(2kx)youcanIBP→......
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