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Question Number 155533 by mnjuly1970 last updated on 01/Oct/21

$$$$$$coefficiientof{x}^{60}=?$$$$$$$$\mathrm{P}=(x-1)(x^2-1)(x^3-1)...(x^{15}-1)$$$$$$

Answered by qaz last updated on 02/Oct/21

$$\frac{1}{2\pi \mathrm{i}}{\int }_{\mid \mathrm{z}\mid =ϵ}\frac{(\mathrm{z}-1)({\mathrm{z}}^2-1)({\mathrm{z}}^3-1)...({\mathrm{z}}^{15}-1)}{{\mathrm{z}}^{61}}\mathrm{dz}$$

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