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Question Number 155583 by cortano last updated on 02/Oct/21

Answered by yeti123 last updated on 02/Oct/21

$$x=6.4172604685892...$$$$x\approx 6.417260$$

Answered by peter frank last updated on 02/Oct/21

$$\mathrm{x}-5\log (5\mathrm{x}-2)=2\mathrm{x}+1\log (\mathrm{x}-5)$$$$\left(\frac{\mathrm{x}-5}{2\mathrm{x}+1}\right)\log (5\mathrm{x}-2)-\log (\mathrm{x}-5)=0$$$$....$$$$$$

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