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Question Number 155631 by aunzo last updated on 03/Oct/21

$$(x+3(x-2)=x+10$$

Commented by aunzo last updated on 03/Oct/21

$$plss$$

Commented by Ar Brandon last updated on 03/Oct/21

$$\mathrm{syntax}\mathrm{error}!$$

Answered by Rasheed.Sindhi last updated on 03/Oct/21

$$If{it}^{\prime }sas(x+3)(x-2)=x+10$$$$x^2+x-6=x+10$$$$x^2-6=10$$$$x^2=10+6=16$$$$x=\pm 4$$$$If{it}^{\prime }sas(x+3(x-2))=x+10$$$$x+3x-6=x+10$$$$4x-x=10+6=16$$$$3x=16$$$$x=\frac{16}{3}=5\frac{1}{3}$$

Answered by peter frank last updated on 03/Oct/21

$$\mathrm{x}+3(\mathrm{x}-2)=\mathrm{x}+10$$$$\mathrm{x}+3\mathrm{x}-6=\mathrm{x}+10$$$$4\mathrm{x}-6=\mathrm{x}+10$$$$3\mathrm{x}=16$$$$\mathrm{x}=\frac{16}{3}$$

Commented by ajfour last updated on 03/Oct/21

good notice!

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