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Question Number 155642 by mathlove last updated on 03/Oct/21

Commented by cortano last updated on 03/Oct/21

$$8\sqrt{2}\ln {}^2\left(3\right)$$

Commented by mathlove last updated on 03/Oct/21

$$solution$$

Commented by cortano last updated on 03/Oct/21

$$\frac{1}{\sqrt{2}}\underset{x\to 0}{\lim }{\left(\frac{3^{\mathrm{x}}-1}{\mathrm{x}}\right)}^2{\left(\frac{\mathrm{x}}{\sin \frac{1}{4}\mathrm{x}}\right)}^2=$$$$\frac{1}{\sqrt{2}}\times {\left(\ln 3\right)}^2\times 16$$

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