Question and Answers Forum

All Questions      Topic List

Coordinate Geometry Questions

Previous in All Question      Next in All Question      

Previous in Coordinate Geometry      Next in Coordinate Geometry      

Question Number 155735 by BHOOPENDRA last updated on 04/Oct/21

Answered by ajfour last updated on 04/Oct/21

Commented by ajfour last updated on 04/Oct/21

x^2 +(y−(1/2))^2 =1^2 +((1/2))^2   ⇒ x^2 +y^2 −y−1=0

$${x}^{\mathrm{2}} +\left({y}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{1}^{\mathrm{2}} +\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} \\ $$$$\Rightarrow\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −{y}−\mathrm{1}=\mathrm{0} \\ $$

Commented by BHOOPENDRA last updated on 04/Oct/21

nice sir

$${nice}\:{sir} \\ $$

Commented by BHOOPENDRA last updated on 04/Oct/21

which option is correct ?

$${which}\:{option}\:{is}\:{correct}\:? \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com