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Question Number 155757 by aliyn last updated on 04/Oct/21

2x^2  (dy/dx) − 2x^2  = (x−1) y^2   ; y(1) = 2     □ M

$$\mathrm{2}\boldsymbol{{x}}^{\mathrm{2}} \:\frac{\boldsymbol{{dy}}}{\boldsymbol{{dx}}}\:−\:\mathrm{2}\boldsymbol{{x}}^{\mathrm{2}} \:=\:\left(\boldsymbol{{x}}−\mathrm{1}\right)\:\boldsymbol{{y}}^{\mathrm{2}} \:\:;\:\boldsymbol{{y}}\left(\mathrm{1}\right)\:=\:\mathrm{2}\: \\ $$$$ \\ $$$$\square\:\boldsymbol{{M}}\: \\ $$

Commented by tabata last updated on 04/Oct/21

????????

$$???????? \\ $$

Commented by amin96 last updated on 04/Oct/21

there seems to be a lack

$${there}\:{seems}\:{to}\:{be}\:{a}\:{lack} \\ $$$$ \\ $$

Commented by tabata last updated on 04/Oct/21

yes sir im also think this

$$\boldsymbol{{yes}}\:\boldsymbol{{sir}}\:\boldsymbol{{im}}\:\boldsymbol{{also}}\:\boldsymbol{{think}}\:\boldsymbol{{this}} \\ $$

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