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Question Number 155772 by daus last updated on 04/Oct/21

Answered by mr W last updated on 04/Oct/21

Commented by mr W last updated on 04/Oct/21

$$T(\frac{b}{\sqrt{2}},\frac{b}{\sqrt{2}})$$$$S(a,0)$$$$P(x,y)$$$$y=\frac{0+\frac{b}{\sqrt{2}}}{2}=\frac{b}{2\sqrt{2}}\Rightarrow b=2\sqrt{2}y$$$$x=\frac{a+\frac{b}{\sqrt{2}}}{2}=\frac{a}{2}+y\Rightarrow a=2(x-y)$$$$letST=l=2$$$$l^2=a^2+b^2-\sqrt{2}ab$$$$l^2=8y^2+4{(x-y)}^2-8y(x-y)$$$$\Rightarrow x^2+5y^2-4xy={\left(\frac{l}{2}\right)}^2$$$$thisisanellipse.$$

Commented by mr W last updated on 04/Oct/21

Commented by daus last updated on 05/Oct/21

$$thanks$$

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