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Question Number 155866 by cherokeesay last updated on 05/Oct/21

Answered by talminator2856791 last updated on 05/Oct/21

$$2\sqrt{3}+2\sqrt{3}-\frac{9\pi \cdot \arctan \left(\frac{2\sqrt{3}}{2}\right)}{2\pi }-\frac{\pi }{4}-\frac{\arctan \left(\frac{2}{2\sqrt{3}}\right)}{2}$$$$=4\sqrt{3}-\frac{9}{2}\arctan \left(\sqrt{3}\right)-\frac{\pi }{4}-\arctan \left(\frac{1}{\sqrt{3}}\right)$$$$=4\sqrt{3}-\frac{9\pi }{6}-\frac{\pi }{4}-\frac{\pi }{6}$$$$=4\sqrt{3}-\frac{13\pi }{12}$$

Commented by cherokeesay last updated on 05/Oct/21

$$\frac{13\pi }{12}\left(error\right)$$

Commented by cherokeesay last updated on 05/Oct/21

$$4\sqrt{3}-\frac{11\pi }{6}$$

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