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Question Number 155989 by cortano last updated on 07/Oct/21

$$5\sin {}^{2}2\mathrm{x}+8\cos {}^3\mathrm{x}=8\cos \mathrm{x}$$$$\frac{3\pi }{2}⩽\mathrm{x}⩽2\pi$$

Commented by john_santu last updated on 07/Oct/21

$$x=\frac{3\pi }{2},2\pi -\arccos \frac{2}{3},2\pi$$

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