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Question Number 156080 by SANOGO last updated on 07/Oct/21

$$\int e^{-2x}cos\left(e^{-x}\right)dx$$

Commented by ARUNG_Brandon_MBU last updated on 07/Oct/21

$$u=e^{-x}\Rightarrow du=-e^{-x}dx=$$$$I=\int e^{-x}\cos \left(e^{-x}\right)\cdot e^{-x}dx$$$$=-\int u\cos \left(u\right)du=-[u\sin x+\cos x]+C$$

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