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Question Number 15610 by RasheedSoomro last updated on 12/Jun/17

The temperature of some 100 litres  is 80°C.  10 litres water,whose temperature  is 100°C is mixed in it.What will be the  temperature of mixed water?

$$\mathrm{The}\:\mathrm{temperature}\:\mathrm{of}\:\mathrm{some}\:\mathrm{100}\:\mathrm{litres} \\ $$$$\mathrm{is}\:\mathrm{80}°\mathrm{C}.\:\:\mathrm{10}\:\mathrm{litres}\:\mathrm{water},\mathrm{whose}\:\mathrm{temperature} \\ $$$$\mathrm{is}\:\mathrm{100}°\mathrm{C}\:\mathrm{is}\:\mathrm{mixed}\:\mathrm{in}\:\mathrm{it}.\mathrm{What}\:\mathrm{will}\:\mathrm{be}\:\mathrm{the} \\ $$$$\mathrm{temperature}\:\mathrm{of}\:\mathrm{mixed}\:\mathrm{water}? \\ $$

Commented by RasheedSoomro last updated on 12/Jun/17

Thanks Sir!

$$\mathrm{Thanks}\:\mathrm{Sir}! \\ $$

Commented by mrW1 last updated on 12/Jun/17

x=((100×80+10×100)/(110))  =((9000)/(110))=81.8 °C

$$\mathrm{x}=\frac{\mathrm{100}×\mathrm{80}+\mathrm{10}×\mathrm{100}}{\mathrm{110}} \\ $$$$=\frac{\mathrm{9000}}{\mathrm{110}}=\mathrm{81}.\mathrm{8}\:°\mathrm{C} \\ $$

Commented by mrW1 last updated on 12/Jun/17

our experience tells us the mixed  water must be > 80° and < 100° warm.

$$\mathrm{our}\:\mathrm{experience}\:\mathrm{tells}\:\mathrm{us}\:\mathrm{the}\:\mathrm{mixed} \\ $$$$\mathrm{water}\:\mathrm{must}\:\mathrm{be}\:>\:\mathrm{80}°\:\mathrm{and}\:<\:\mathrm{100}°\:\mathrm{warm}. \\ $$

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