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Question Number 156138 by SANOGO last updated on 08/Oct/21

$$lavaleurde{l}^{\prime }integrale$$$${\underset{o}{\int }}^{1}x\sqrt{\sqrt{\sqrt{x}}}$$$$$$

Commented by cortano last updated on 08/Oct/21

$${\int }_0^{1}x.x^{1/8}dx={\int }_0^1{x}^{9/8}dx$$$$=\frac{8}{17}{\left[x^{17/8}\right]}_0^1=\frac{8}{17}$$

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