All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 156194 by talminator2856791 last updated on 09/Oct/21
∫01xx2x3.....xndxn∈N
Commented by MJS_new last updated on 10/Oct/21
=∫10x2−n+22ndx=[x3−n+22n3−n+22n]01=2n3×2n−n−2
Terms of Service
Privacy Policy
Contact: info@tinkutara.com