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Question Number 156244 by Eric002 last updated on 09/Oct/21
solvethepairsofsimultaneousequationsax−2y=2x+3y=3qy−px=(q2−p2)/pqpy+qx=2
Answered by MJS_new last updated on 10/Oct/21
(1)x=123a+2∧y=3a−23a+2∧a≠−23(2)x=p2+2pq−q22pq2∧y=−p2−2pq−q22p2q∧p≠0∧q≠0
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