solve the pairs of simultaneous equations ax−2y=2 x+3y=3 qy−px=(q^2 −p^2 )/pq py+qx=2


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Question Number 156244 by Eric002 last updated on 09/Oct/21

$s o l v e t h e p a i r s o f s i m u l t a n e o u s e q u a t i o n s$ $a x - 2 y = 2$ $x + 3 y = 3$ $q y - p x = (q^{2} - p^{2}) / p q$ $p y + q x = 2$
	Answered by MJS_new last updated on 10/Oct/21

	$(1) x = \frac{12}{3 a + 2} \land y = \frac{3 a - 2}{3 a + 2} \land a \neq - \frac{2}{3}$ $(2) x = \frac{p^{2} + 2 p q - q^{2}}{2 {p q}^{2}} \land y = - \frac{p^{2} - 2 p q - q^{2}}{2 p^{2} q} \land p \neq 0 \land q \neq 0$
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