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Question Number 115999 by bemath last updated on 30/Sep/20
limx→01−cosxcos2xcos3x3cos4x4x2
Answered by bobhans last updated on 30/Sep/20
shortcut′mrjohnsantu′limx→01−cosxcos2xcos3x3cos4x4x2=12(12+222+323+424)=12(1+2+3+4)=5
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