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Question Number 156369 by tabata last updated on 10/Oct/21

$$solvebybettafunction{\int }_0^{2\pi }{sin}^5\left(z\right)dz$$

Commented by tabata last updated on 10/Oct/21

$$????????$$

Commented by aliyn last updated on 10/Oct/21

$$??????$$

Answered by Mathspace last updated on 11/Oct/21

$${\int }_0^{2\pi }{sin}^{5}xdx$$$$$$$$={\int }_0^{\pi }{sin}^{5}xdx+{\int }_{\pi }^{2\pi }{sin}^{5}xdx(\to x=\pi +u)$$$$={\int }_0^{\pi }{sin}^{5}xdx+{\int }_0^{\pi }(-{sin}^{5}u)du$$$$=0(noneedforbetta...!)$$$$$$$$$$

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