if 1≤x ; y≤2 ; 3≤z ; t≤4 prove that: ((x^2 +y^2 +1)/(xz+yt+3)) + ((√6)/3) ≤ ((3+xz+yt)/(9+z^2 +t^2 )) + ((11)/(12))


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Question Number 156661 by MathSh last updated on 13/Oct/21

$if 1 ⩽ x; y ⩽ 2; 3 ⩽ z; t ⩽ 4 prove that :$ $\frac{x^{2} + y^{2} + 1}{xz + yt + 3} + \frac{\sqrt{6}}{3} ⩽ \frac{3 + xz + yt}{9 + z^{2} + t^{2}} + \frac{11}{12}$
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