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Question Number 15667 by tawa tawa last updated on 12/Jun/17

Commented by mrW1 last updated on 12/Jun/17

$$\mathrm{diagram}\mathrm{is}\mathrm{not}\mathrm{to}\mathrm{understand}.\mathrm{please}$$$$\mathrm{give}\mathrm{a}\mathrm{clear}\mathrm{diagram}.$$

Commented by tawa tawa last updated on 12/Jun/17

Answered by mrW1 last updated on 12/Jun/17

$$\mathrm{a}.$$$$\stackrel{⌢}{\mathrm{AB}}=\frac{90}{360}\times 2\times 7\times \pi =\frac{7\pi }{2}\mathrm{cm}$$$$\mathrm{b}.$$$${\mathrm{A}}_{\mathrm{O}\stackrel{⌢}{\mathrm{AB}}}=\frac{90}{360}\times 7^2\times \pi =\frac{49\pi }{4}{\mathrm{cm}}^2$$$$\mathrm{c}.$$$${\mathrm{P}}_{\mathrm{O}\stackrel{⌢}{\mathrm{AB}}}=2\times 7+\frac{7\pi }{2}=14+\frac{7\pi }{2}\mathrm{cm}$$$$\mathrm{d}.$$$$\mathrm{AB}=2\times 7\times \sin \frac{90}{2}=2\times 7\times \frac{\sqrt{2}}{2}=7\sqrt{2}\mathrm{cm}$$$$\mathrm{e}.$$$${\mathrm{A}}_{\mathrm{ABC}}=\frac{49\pi }{4}-\frac{7\times 7}{2}=\frac{49\pi }{4}-\frac{49}{2}{\mathrm{cm}}^2$$$$\mathrm{f}.$$$${\mathrm{P}}_{\mathrm{ABC}}=\frac{7\pi }{2}+7\sqrt{2}\mathrm{cm}$$

Commented by mrW1 last updated on 12/Jun/17

Commented by tawa tawa last updated on 12/Jun/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{i}\mathrm{really}\mathrm{appreciate}.$$

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