Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 156775 by mnjuly1970 last updated on 15/Oct/21

     f  is  a function that assigns     to each natural number        multiplication of its digits       for exampl :  f( 200)=0      f ( 128 )=1×2×8 =16       find the value of :       f (100) + f(101 )+ f (102 )+...f(999)=?

fisafunctionthatassignstoeachnaturalnumbermultiplicationofitsdigitsforexampl:f(200)=0f(128)=1×2×8=16findthevalueof:f(100)+f(101)+f(102)+...f(999)=?

Commented by Rasheed.Sindhi last updated on 15/Oct/21

Σ_(a=1,b=0,c=0) ^(a=9,b=9,c=9) abc=91125

a=9,b=9,c=9a=1,b=0,c=0abc=91125

Answered by Rasheed.Sindhi last updated on 15/Oct/21

100≤abc^(−) ≤999  c=0,1,2,...,9  ab0^(−) ,ab1^(−) ,ab2^(−) ,...ab9^(−)   f(ab0^(−) )+f(ab1^(−) )+f(ab2^(−) )+,...+f(ab9^(−) )  =a.b.0+a.b.1+a.b.2+...+a.b.9  =ab(0+1+2+3+...+9)  =ab(((9×10)/2))=ab(45)  b=0,1,2,...,9  a.b(45):   45a.0+45a.1+45a.2+...+45a.9  =45a(0+1+2+...+9)=45^2 a  a=1,2,3,...,9  45^2 a:  45^2 .1+45^2 .2+45^2 .3+...+45^2 .9  45^2 (1+2+3+...+9)=45^3 =91125         By my son, Arshad Soomro

100abc999c=0,1,2,...,9ab0,ab1,ab2,...ab9f(ab0)+f(ab1)+f(ab2)+,...+f(ab9)=a.b.0+a.b.1+a.b.2+...+a.b.9=ab(0+1+2+3+...+9)=ab(9×102)=ab(45)b=0,1,2,...,9a.b(45):45a.0+45a.1+45a.2+...+45a.9=45a(0+1+2+...+9)=452aa=1,2,3,...,9452a:452.1+452.2+452.3+...+452.9452(1+2+3+...+9)=453=91125Bymyson,ArshadSoomro

Commented by mnjuly1970 last updated on 16/Oct/21

very nice thanks alot ...

verynicethanksalot...

Commented by qaz last updated on 15/Oct/21

S=Σ_(a=1) ^9 Σ_(b=1) ^9 Σ_(c=1) ^9 abc=Σ_(a=1) ^9 aΣ_(b=1) ^9 bΣ_(c=1) ^9 c=(((9∙10)/2))^3 =91125

S=9a=19b=19c=1abc=9a=1a9b=1b9c=1c=(9102)3=91125

Terms of Service

Privacy Policy

Contact: info@tinkutara.com