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Question Number 157031 by PRITHWISH SEN 2 last updated on 18/Oct/21

$$\mathrm{If}\mathrm{xcos}\theta +\mathrm{ycos}\mathrm{\varnothing }+\mathrm{zcos}\psi =0,$$$$\mathrm{xsin}\theta +\mathrm{ysin}\mathrm{\varnothing }+\mathrm{zsin}\psi =0$$$$\mathrm{and}\mathrm{xsec}\theta +\mathrm{ysec}\mathrm{\varnothing }+\mathrm{zsec}\psi =0$$$$\mathrm{then}\mathrm{prove}\mathrm{that}$$$${({\mathrm{x}}^2+{\mathrm{y}}^2-{\mathrm{z}}^2)}^2={4\mathrm{x}}^2{\mathrm{y}}^2$$

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