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Question Number 157074 by amin96 last updated on 19/Oct/21

$$\sqrt{4+\sqrt{4^2+\sqrt{4^3+\sqrt{4^4+\dots }}}}=?$$

Answered by MJS_new last updated on 19/Oct/21

$$3$$

Commented by amin96 last updated on 19/Oct/21

$$????$$

Commented by MJS_new last updated on 19/Oct/21

$$!!!!$$

Answered by Javokhir last updated on 19/Oct/21

$$\mathrm{a}+2=\sqrt{4+\mathrm{a}\sqrt{16+\mathrm{a}\sqrt{64+\mathrm{a}\sqrt{256+.....}}}}$$$$\mathrm{a}=1\iff 3=\sqrt{4+\sqrt{16+\sqrt{64+\sqrt{256+...}}}}$$

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