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Question Number 157227 by amin96 last updated on 21/Oct/21
x(3sin(x)−2x)=sin3(x)
Answered by Javokhir last updated on 21/Oct/21
x=tt2(3sint−2t)=sin3t(t=0✓)t≠03−2tsint=sin2tt2⇒sintt=zz2=3−2z⇒z3−3z+2=0z3−z−2(z−1)=0(z2−2)(z−1)=0⇔sint=tsint=2tsint=−2t..................
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