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Question Number 157267 by cortano last updated on 21/Oct/21

$$(1+x^2)y^{″}-2{xy}^{\prime }+2y=x$$

Commented by MathsFan last updated on 22/Oct/21

$$anycaption????$$

Commented by john_santu last updated on 22/Oct/21

$$y=c_1(x^2-1)+c_{2}x-\frac{1}{2}x(1+\ln (1+x^2))+\frac{1}{2}(x^2-1){\tan }^{-1}\left(x\right)$$

Commented by tabata last updated on 23/Oct/21

$$how????$$

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