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Question Number 157392 by ajfour last updated on 22/Oct/21

Commented by ajfour last updated on 22/Oct/21

$$Theyarereleasedasshown.$$

Commented by mr W last updated on 23/Oct/21

$$hardquestion...$$

Answered by ajfour last updated on 23/Oct/21

$${(b+r)}^2+{(a+r)}^2={(a+b)}^2$$$$\Rightarrow r^2+(a+b)r-ab=0$$$${(r+\frac{a+b}{2})}^2={\left(\frac{a+b}{2}\right)}^2+ab$$$$r=\sqrt{\frac{a^2+b^2+6ab}{4}}-\frac{a+b}{2}$$$$...$$

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